#P3609. Up-up

    ID: 2493 远端评测题 1000ms 32MiB 尝试: 0 已通过: 0 难度: (无) 上传者: 标签>2010 ACM-ICPC Multi-University Training Contest(17)——Host by ZSTU

Up-up

Problem Description

The Up-up of a number a by a positive integer b, denoted by a↑↑b, is recursively defined by:
a↑↑1 = a,
a↑↑(k+1) = a (a↑↑k)
Thus we have e.g. 3↑↑2 = 33 = 27, hence 3↑↑3 = 327= 7625597484987 and 3↑↑4 is roughly 103.6383346400240996*10^12
The problem is give you a pair of a and k,you must calculate a↑↑k ,the result may be large you can output the answer mod 100000000 instead

Input

A pair of a and k .a is a positive integer and fit in __int64 and 1<=k<=200

Output

a↑↑k mod 100000000

3 2 3 3
27 97484987